# In parallelogram ABCD, the angle ABC is 150 °. The bisector of angle B intersects

October 1, 2021 | education

| **In parallelogram ABCD, the angle ABC is 150 °. The bisector of angle B intersects side AD at point K. Find the magnitude of the angle BKD in degrees.**

The bisector BK divides the angle ABC into two equal angles:

<ABC = <KBC = 150 ° / 2 = 75 °.

The angles KBC and BKD are internal one-sided angles obtained by cutting parallel sides with a bisector:

<KBC + <BKD = 180 °;

<BKD = 180 ° – <KBC = 180 ° – 75 ° = 105 °.

Answer: 105 °.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.